Comments on: Tip: Passing Parameters http://blog.usepowershell.com/2009/03/tip-passing-parameters/ The Shell Is Calling Tue, 10 Jan 2012 04:24:21 +0000 hourly 1 http://wordpress.org/?v=3.1.3 By: Brian.Christiansen http://blog.usepowershell.com/2009/03/tip-passing-parameters/comment-page-1/#comment-950 Brian.Christiansen Fri, 11 Nov 2011 05:20:47 +0000 http://blog.usepowershell.com/2009/03/tip-passing-parameters/#comment-950 Thanks for the tip about "Passing Parameters" One of the points raised in the post was about passing a text datatype parameter to a procedure called in the background and the fact that the contents of the text variable are lost. The same code called in the foreground works at both parameters are being passed as one is that PowerShell does not use the parens “()” to enclose parameters (that is only method calls from objects).Thanks Steven Murawski. Thanks for the tip about “Passing Parameters” One of the points raised in the post was about passing a text datatype parameter to a procedure called in the background and the fact that the contents of the text variable are lost. The same code called in the foreground works at both parameters are being passed as one is that PowerShell does not use the parens “()” to enclose parameters (that is only method calls from objects).Thanks Steven Murawski.

]]> By: Steven Murawski http://blog.usepowershell.com/2009/03/tip-passing-parameters/comment-page-1/#comment-140 Steven Murawski Tue, 04 Aug 2009 15:23:40 +0000 http://blog.usepowershell.com/2009/03/tip-passing-parameters/#comment-140 Orlando, The reason that both parameters are being passed as one is that PowerShell does not use the parens "()" to enclose parameters (that is only method calls from objects). Your function is only seeing one parameter being passed - an array containing $result and $logPreInstall. Try changing your function call to WriteVerifyLog $result $logPreInstall and you should see the desired results. Orlando,
The reason that both parameters are being passed as one is that PowerShell does not use the parens “()” to enclose parameters (that is only method calls from objects). Your function is only seeing one parameter being passed – an array containing $result and $logPreInstall.
Try changing your function call to
WriteVerifyLog $result $logPreInstall
and you should see the desired results.

]]> By: orlando http://blog.usepowershell.com/2009/03/tip-passing-parameters/comment-page-1/#comment-139 orlando Tue, 04 Aug 2009 14:31:30 +0000 http://blog.usepowershell.com/2009/03/tip-passing-parameters/#comment-139 HI, I have a question regarding passing the parameters to a function like this: function WriteVerifyLog($message, $logFile){ [string]$m=$message; if ($m.contains('successfully')) {continue} else{ Add-Content -Value $message -Path $LogFile; } } when I call the function: WriteVerifyLog($result, $logPreInstall); draws my attention that $message contains both the value of $result AND $logPreInstall. I don't know what's the reason, and I like to ask your feedback on that. I'd expect that $logFile would take the value of $logPreInstall. what am I doing wrong? Thanks in advance for the reply. HI, I have a question regarding passing the parameters to a function like this:
function WriteVerifyLog($message, $logFile){
[string]$m=$message;
if ($m.contains(‘successfully’)) {continue}
else{
Add-Content -Value $message -Path $LogFile;
}

}

when I call the function:
WriteVerifyLog($result, $logPreInstall);
draws my attention that $message contains both the value of $result AND $logPreInstall. I don’t know what’s the reason, and I like to ask your feedback on that. I’d expect that $logFile would take the value of $logPreInstall. what am I doing wrong? Thanks in advance for the reply.

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